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	<title>Comments on: Moments &#8211; Turning Forces</title>
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	<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/</link>
	<description>Maths help and revision for GCSE, A/AS Level and Further Maths</description>
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		<title>By: Sri Yuliani</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/comment-page-1/#comment-161</link>
		<dc:creator>Sri Yuliani</dc:creator>
		<pubDate>Mon, 23 Mar 2009 03:40:31 +0000</pubDate>
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		<description>I think Denaya&#039;s comment is correct, because the Calandra method is always based on finding a number that has nearest square but still smaller than the number that to be calculated it&#039;s square root. So, for square root of 4, the Calandra method yeilds 1.999999... not precise 2.</description>
		<content:encoded><![CDATA[<p>I think Denaya&#8217;s comment is correct, because the Calandra method is always based on finding a number that has nearest square but still smaller than the number that to be calculated it&#8217;s square root. So, for square root of 4, the Calandra method yeilds 1.999999&#8230; not precise 2.</p>
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		<title>By: Nadya Fermega</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/comment-page-1/#comment-160</link>
		<dc:creator>Nadya Fermega</dc:creator>
		<pubDate>Sun, 22 Mar 2009 01:58:09 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=150#comment-160</guid>
		<description>Denaya, 4=2*2, so  mr.Dave need not Calandra method to calculate the square root of 4, coz it is equal 2, isn&#039;t it?.</description>
		<content:encoded><![CDATA[<p>Denaya, 4=2*2, so  mr.Dave need not Calandra method to calculate the square root of 4, coz it is equal 2, isn&#8217;t it?.</p>
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		<title>By: Denaya Lesa</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/comment-page-1/#comment-159</link>
		<dc:creator>Denaya Lesa</dc:creator>
		<pubDate>Sat, 21 Mar 2009 11:27:21 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=150#comment-159</guid>
		<description>Of course @Dave, like for pi number we are imposible to write square root of a number in fractional form. Denaya believes  Dave still remember that world has Calandra method as the simpliest method for calculating square root. Unfortunately Calandra method is still difficult to get the root of 3, even it can&#039;t gives the root of 4.</description>
		<content:encoded><![CDATA[<p>Of course @Dave, like for pi number we are imposible to write square root of a number in fractional form. Denaya believes  Dave still remember that world has Calandra method as the simpliest method for calculating square root. Unfortunately Calandra method is still difficult to get the root of 3, even it can&#8217;t gives the root of 4.</p>
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		<title>By: trevorpythag</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/comment-page-/#comment-158</link>
		<dc:creator>trevorpythag</dc:creator>
		<pubDate>Thu, 19 Mar 2009 16:36:21 +0000</pubDate>
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		<description>root 3 can be proved to be irrational so im unsure what you mean by getting the value of root 3 as it cant be written as a fraction or finite/recurring decimal.

though I would be glad to help
dave,</description>
		<content:encoded><![CDATA[<p>root 3 can be proved to be irrational so im unsure what you mean by getting the value of root 3 as it cant be written as a fraction or finite/recurring decimal.</p>
<p>though I would be glad to help<br />
dave,</p>
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		<title>By: Denaya Lesa</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/comment-page-1/#comment-157</link>
		<dc:creator>Denaya Lesa</dc:creator>
		<pubDate>Thu, 19 Mar 2009 09:51:24 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=150#comment-157</guid>
		<description>Apologise Mr.Rohedi, Denaya is now more interested to the expression of √3, cos we&#039;ve just celebrated the square root day on 3/3/9. Would you help @Dave in getting the value of √3 by simple way?</description>
		<content:encoded><![CDATA[<p>Apologise Mr.Rohedi, Denaya is now more interested to the expression of √3, cos we&#8217;ve just celebrated the square root day on 3/3/9. Would you help @Dave in getting the value of √3 by simple way?</p>
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		<title>By: Rohedi</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/mechanics/moments-turning-forces/comment-page-1/#comment-156</link>
		<dc:creator>Rohedi</dc:creator>
		<pubDate>Wed, 18 Mar 2009 19:44:55 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=150#comment-156</guid>
		<description>Excelent explanation, but it is still to be stressed that basically the moment is defined as the multiplication between a force with it&#039;s lever respect to the pivot point. By this definition, the readers understand why both of sine and cosine functions can involve on the moment expression.</description>
		<content:encoded><![CDATA[<p>Excelent explanation, but it is still to be stressed that basically the moment is defined as the multiplication between a force with it&#8217;s lever respect to the pivot point. By this definition, the readers understand why both of sine and cosine functions can involve on the moment expression.</p>
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