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	<title>Comments on: Differentiate Inverse Cos &#8211; Proof</title>
	<atom:link href="http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/feed/" rel="self" type="application/rss+xml" />
	<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/</link>
	<description>Maths help and revision for GCSE, A/AS Level and Further Maths</description>
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	<item>
		<title>By: admin</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-19067</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Tue, 08 May 2012 11:11:38 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-19067</guid>
		<description>&lt;a href=&quot;#comment-18941&quot; rel=&quot;nofollow&quot;&gt;@No &lt;/a&gt; 
Look back at the start:
We are trying to differentiate the function y = cos-1(x) but this is equivalent to cosy = x (by definition of cos-1)
So then where we ave cos^2(y) in the line above it becomes x^2 by substitution</description>
		<content:encoded><![CDATA[<p><a href="#comment-18941" rel="nofollow">@No </a><br />
Look back at the start:<br />
We are trying to differentiate the function y = cos-1(x) but this is equivalent to cosy = x (by definition of cos-1)<br />
So then where we ave cos^2(y) in the line above it becomes x^2 by substitution</p>
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	<item>
		<title>By: No</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-18941</link>
		<dc:creator>No</dc:creator>
		<pubDate>Sun, 06 May 2012 23:16:30 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-18941</guid>
		<description>Oh Come on!!! I got it all the way till &quot;dy/dx = -1/√(1-cos2y)&quot; but then you said &quot;but cosy = x so...   dy/dx =- 1/√(1-x2)&quot;, Not clear on how and why it is. You didn&#039;t explain how you went from that to this dy/dx =- 1/√(1-x2)????
Thanks</description>
		<content:encoded><![CDATA[<p>Oh Come on!!! I got it all the way till &#8220;dy/dx = -1/√(1-cos2y)&#8221; but then you said &#8220;but cosy = x so&#8230;   dy/dx =- 1/√(1-x2)&#8221;, Not clear on how and why it is. You didn&#8217;t explain how you went from that to this dy/dx =- 1/√(1-x2)????<br />
Thanks</p>
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	<item>
		<title>By: trevorpythag</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-123</link>
		<dc:creator>trevorpythag</dc:creator>
		<pubDate>Mon, 09 Feb 2009 17:51:40 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-123</guid>
		<description>oops sorry thanks for pointing it out
dave</description>
		<content:encoded><![CDATA[<p>oops sorry thanks for pointing it out<br />
dave</p>
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	<item>
		<title>By: Barbara</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-122</link>
		<dc:creator>Barbara</dc:creator>
		<pubDate>Sun, 08 Feb 2009 22:07:05 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-122</guid>
		<description>You&#039;ve missed the minus!!!
d/dy(arccos) = - 1/ sq(1-x^2)</description>
		<content:encoded><![CDATA[<p>You&#8217;ve missed the minus!!!<br />
d/dy(arccos) = &#8211; 1/ sq(1-x^2)</p>
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	<item>
		<title>By: Nadya Fermega</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-118</link>
		<dc:creator>Nadya Fermega</dc:creator>
		<pubDate>Wed, 14 Jan 2009 09:53:40 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-118</guid>
		<description>@Denaya

No no no, you are wrong Denaya, rohedi&#039;s comment corresponds to your purpose is at this address

http://unapologetic.wordpress.com/2008/10/13/sine-and-cosine/

when Mr. Rohedi solves f&#039;&#039;+f=0

I think you have done big blunder, huahuahau...sorry honey.</description>
		<content:encoded><![CDATA[<p>@Denaya</p>
<p>No no no, you are wrong Denaya, rohedi&#8217;s comment corresponds to your purpose is at this address</p>
<p><a href="http://unapologetic.wordpress.com/2008/10/13/sine-and-cosine/" rel="nofollow">http://unapologetic.wordpress.com/2008/10/13/sine-and-cosine/</a></p>
<p>when Mr. Rohedi solves f&#8221;+f=0</p>
<p>I think you have done big blunder, huahuahau&#8230;sorry honey.</p>
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	<item>
		<title>By: Nadya Fermega</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-121</link>
		<dc:creator>Nadya Fermega</dc:creator>
		<pubDate>Wed, 14 Jan 2009 09:52:15 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-121</guid>
		<description>@Denaya

No no no, you are wrong Denaya, rohedi&#039;s comment corresponds to your purpose is at this address

http://unapologetic.wordpress.com/2008/10/13/sine-and-cosine/

when Mr. Rohedi solves f&#039;&#039;+f=0

I think you have done big blunder, huahuahau...</description>
		<content:encoded><![CDATA[<p>@Denaya</p>
<p>No no no, you are wrong Denaya, rohedi&#8217;s comment corresponds to your purpose is at this address</p>
<p><a href="http://unapologetic.wordpress.com/2008/10/13/sine-and-cosine/" rel="nofollow">http://unapologetic.wordpress.com/2008/10/13/sine-and-cosine/</a></p>
<p>when Mr. Rohedi solves f&#8221;+f=0</p>
<p>I think you have done big blunder, huahuahau&#8230;</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Denaya Lesa</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-120</link>
		<dc:creator>Denaya Lesa</dc:creator>
		<pubDate>Wed, 14 Jan 2009 09:42:33 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-120</guid>
		<description>Hmm, if you want to know an application of both cos-1(x) and sin-1(x) simultaneously, please read rohedi&#039;s comment on

http://unapologetic.wordpress.com/2008/10/10/the-exponential-differential-equation/.</description>
		<content:encoded><![CDATA[<p>Hmm, if you want to know an application of both cos-1(x) and sin-1(x) simultaneously, please read rohedi&#8217;s comment on</p>
<p><a href="http://unapologetic.wordpress.com/2008/10/10/the-exponential-differential-equation/" rel="nofollow">http://unapologetic.wordpress.com/2008/10/10/the-exponential-differential-equation/</a>.</p>
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	</item>
	<item>
		<title>By: Denaya Lesa</title>
		<link>http://trevorpythag.co.uk/2009/mathematics/algebra/differentiate-inverse-cos-proof/comment-page-1/#comment-119</link>
		<dc:creator>Denaya Lesa</dc:creator>
		<pubDate>Wed, 14 Jan 2009 09:20:13 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=112#comment-119</guid>
		<description>He he he, I think you must take the following conclusions:

   the differentiate of cos-1(x) is  dy/dx = - 1/√(1-x2)

while

 the differentiate of sin-1(x) is  dy/dx =  1/√(1-x2)

How about you all?</description>
		<content:encoded><![CDATA[<p>He he he, I think you must take the following conclusions:</p>
<p>   the differentiate of cos-1(x) is  dy/dx = &#8211; 1/√(1-x2)</p>
<p>while</p>
<p> the differentiate of sin-1(x) is  dy/dx =  1/√(1-x2)</p>
<p>How about you all?</p>
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