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	<title>Comments on: Complex/Imaginary numbers</title>
	<atom:link href="http://trevorpythag.co.uk/2008/09/28/compleximaginary-numbers/feed/" rel="self" type="application/rss+xml" />
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		<title>By: trevorpythag</title>
		<link>http://trevorpythag.co.uk/2008/09/28/compleximaginary-numbers/comment-page-1/#comment-102</link>
		<dc:creator>trevorpythag</dc:creator>
		<pubDate>Sat, 06 Dec 2008 17:37:04 +0000</pubDate>
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		<description>you can treat them like you would in normal algebra but whenever you get a i squared you can chnage it to -1
ie in your example the answer would be
&lt;strong&gt;(-4i)(-5i)(3i)  = -60i&lt;/strong&gt;
 beacuse 4x5x3 = 20 and i x i x i = -i
hope that helps dave</description>
		<content:encoded><![CDATA[<p>you can treat them like you would in normal algebra but whenever you get a i squared you can chnage it to -1<br />
ie in your example the answer would be<br />
<strong>(-4i)(-5i)(3i)  = -60i</strong><br />
 beacuse 4&#215;5x3 = 20 and i x i x i = -i<br />
hope that helps dave</p>
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		<title>By: aroosa</title>
		<link>http://trevorpythag.co.uk/2008/09/28/compleximaginary-numbers/comment-page-1/#comment-101</link>
		<dc:creator>aroosa</dc:creator>
		<pubDate>Sat, 06 Dec 2008 00:57:26 +0000</pubDate>
		<guid isPermaLink="false">http://trevorpythag.wordpress.com/?p=57#comment-101</guid>
		<description>how do i simply multiply imaginary numbers?

like;

(-4i)(-5i)(3i)</description>
		<content:encoded><![CDATA[<p>how do i simply multiply imaginary numbers?</p>
<p>like;</p>
<p>(-4i)(-5i)(3i)</p>
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